11=16t^2-17t-7

Solution for 11=16t^2-17t-7 equation:

11=16t^2-17t-7

We move all terms to the left:

11-(16t^2-17t-7)=0

We get rid of parentheses

-16t^2+17t+7+11=0

We add all the numbers together, and all the variables

-16t^2+17t+18=0

a = -16; b = 17; c = +18;
Δ = b2-4ac
Δ = 172-4·(-16)·18
Δ = 1441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-\sqrt{1441}}{2*-16}=\frac{-17-\sqrt{1441}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+\sqrt{1441}}{2*-16}=\frac{-17+\sqrt{1441}}{-32}
$